# A body with a specific heat capacity of 500 J / kg * K falls freely from a height of 30 m. How much

October 5, 2021 | education

| **A body with a specific heat capacity of 500 J / kg * K falls freely from a height of 30 m. How much will its temperature increase if 50% of the kinetic energy of the body converts into heat upon ular against the ground?**

To find the temperature change of the fallen body, we will use the formula: η = St * m * Δt / (m * g * h), from where we express: Δt = η * g * h / St.

Constants and variables: η – process efficiency (η = 50% = 0.5); g – acceleration due to gravity (g ≈ 10 m / s2); h – initial body height (h = 30 m); St is the specific heat capacity of the fallen body (St = 500 J / (kg * K)).

Calculation: Δt = η * g * h / St = 0.5 * 10 * 30/500 = 0.3 ºС.

Answer: After the fall, the body increased its temperature by 0.3 ºС.

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